3 years ago

If g(x) = (24 – x)2 + 7, what is the value of g(6)? O 250 O-2 O 243 O 331

Mathematics

1 answer:

valina [46]3 years ago

5 0

$g(x) = (24 - x)2 + 7\\= 48 - 2x + 7\\g(6) = 48 - 2 \cdot 6 + 7\\= 48 - 12 + 7\\= 43$

You might be interested in

What's the answer to this question

sesenic [268]

C. 110. This is because all triangles add up to equal 180*. So you add the two angles you have and subtract from 180.

5 0

2 years ago

The sum of 4 numbers is 1230. The average of 3 of them is 293. What is the fourth number?

OverLord2011 [107]

351 because 293 multiplied by 3 = 879, and 1230 - 879 = 351

8 0

2 years ago

Read 2 more answers

PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS

Elina [12.6K]

You want to end up with $A\sin(\omega t+\phi)$ . Expand this using the angle sum identity for sine:

$A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi$

We want this to line up with $2\sin(4\pi t)+5\cos(4\pi t)$ . Right away, we know $\omega=4\pi$ .

We also need to have

$\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}$

Recall that $\sin^2x+\cos^2x=1$ for all $x$ ; this means

$(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}$

Then

$\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)$

So we end up with

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

8 0

2 years ago

Read 2 more answers

I need helping solving -3z+7=-7-10z

Tpy6a [65]

-3z + 7 = -7 - 10z

Add 10z to both sides

7z + 7 = -7

Subtract 7 from both sides

7z = -14

Divide by 7

Z = -2

8 0

3 years ago

Read 2 more answers

Write the equation of a line that is perpendicular to y=3x-2 and that passes through the point (-9,5)

damaskus [11]

Slope of perpendicular is -1/3.
Then equation is
y-5=(-1/3)(x+9)

8 0

2 years ago