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Alexus [3.1K]
3 years ago
10

How to count from 170 to 410 using tens and hundreds

Mathematics
2 answers:
insens350 [35]3 years ago
4 0
Add 2 hundreds and you get 370 then add 4 tens and get 410
BlackZzzverrR [31]3 years ago
4 0
170+_+_+_+_+_+_=410
170+100+100+10+10+10+10=410 

*so just add 2 hundreds and 4 tens to get 410*
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Four spheres of a radius 6cm just fit inside a cylinder
aksik [14]

Answer:

The space left inside the cyclinder =36π(h - 24)

step-by-step explanation:

Radius of sphere = 6cm

Diameter of cylinder = 12cm

Radius of cylinder = d / 2 = 12 /2 = 6cm

Formula for volume of a sphere = 4/3 πr³

Formula for volume of volume of a cylinder = πr²h

r = radius

h = height

The volume of one sphere = 4/3πr³

Volume of 4 spheres = 4 * 4/3πr³ = 12/3 πr³ = 4πr³

But radius of the sphere = 6cm

Volume of the sphere = 4 * π * 6³

Volume of the sphere = 864π

Let the space left in the cylinder = x

The space left in the cylinder (x) = volume of the cylinder - total volume of the spheres

x = πr²h - 4πr³

Note : both radius = 6cm and we can just substitue it

x = πr² (h - 4r)

x = π*6² (h - 4*6)

x = 36π (h - 24)

The space left inside the cylinder = 36π(h - 24) since we don't know the value of the height of the cylinder.

6 0
3 years ago
PROMPT:
pentagon [3]
For this answer let's pick the Fish Pond.

QUESTION: <span>What do you know? 
We know that the total area of the rectangular patio is 24 square feet. The rectangular fish pond that we want to build should have the length that is twice the width. We also need a 1-foot border around the pond.

The total area of the patio is represented by </span>2 x^{2} +6x+4 where x is the width of the fish pond.

QUESTION: What do you want to find out? 
We can answer this question by examining what we have been given (we have answered this in the previous question). Since we only have one variable in the equation and this is the width of the fish pond, then this is the only thing that we need to find out. The length will just follow after the width is solved. (Basically, we are concerned with the dimensions of our project.)

QUESTION: What kind of answer do you expect? 
Since we are only expecting to solve for the dimensions, then we should expect two numbers which would represent the width and the length. Through the polynomial, we can get the width of our project, then the length would just be twice our answer for the width.

1. To set our polynomial equation equal to the total area of our patio, we just write the equation on the left side and the total area of the patio on the right. We recall the equation that we gave in the first question above as well as the patio's area.

2x^{2} +6x+4=24

2. For this item, we just simply negate the constant term on the right side by subtracting the same number to both sides. Since our constant term is 24, we subtract 24 from the polynomial as well as the term on the right side.

2x^{2} +6x+4-24=24-24
2x^{2} +6x-20=0

3. In this item we are only tasked to find the GCF of the trinomial and factor it out of the left side of the equation. The GCF just means the common number or variable in all terms. Upon examining, we can see that the only common factor of the terms is 2 (since all terms are divisible by 2), thus this will be the GCF and we will factor this one out.

2(x^{2} +3x-10)=0

4. To factor the polynomial completely, we just figure out the possible factors of the quadratic equation. You can do this by trying out all factors of -10 that will have a sum of 3 (since -10 is the constant and 3 is the coefficient of x). Upon examining you should end up with:

2(x+5)(x-2)=0 (Notice that 5 and -2 are factors of -10 and their sum is 3).

5. The rule stated on this item just means that we can equate each individual factor to zero (except for the constant term) to find out the possible values of x. That means that we can solve for x by using the equations x+5=0 and x-2=0.

x+5=0
x=-5

x-2=0
x=2

6. For this item, we just do simple substitutions to the equation 2x^{2} +6x-20=0 to verify whether the values we got in question 5 is really a solution to the equation. The values of x that we got are -5 and 2 so we substitute these one at a time.

2(-5)^{2} +6(-5)-20=0
50-30-20=0
0=0

2(2)^{2} +6(2)-20=0
8+12-20=0
0=0

Both values of x make the left side equal to zero therefore both are solutions to the equation.

7. We can tell the dimensions of the project by looking at the values that we got for x, since we assumed x to be the width of our project. The fact that we got two values for x won't be a problem since one of these values is negative. There is no negative measurement/width so we can just ignore this negative value (-5). Thus, the width for our project would be 2 and the length would be twice this value which is 4.

Width = 2 feet
Length = 4 feet

8. For this item, we just illustrate the dimensions of our project and add a 1-foot border (as we are told initially). You can see this illustration in the picture I attached below. 

Since we have an extra 1 foot in every side, that means we need to add 2 feet to both the width and the length. Therefore, our width now is 4 while our length is 6.

Multiplying these numbers to verify the area, we get 24 square feet which is exactly the area of the patio.

6 0
3 years ago
Read 2 more answers
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