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3 years ago

Determine the molecular weight for mg(no3)2.

Chemistry

2 answers:

eimsori [14]3 years ago

7 0

Answer: The correct answer is 148.33 grams.

Explanation:

To calculate the molecular weight of a compound, we add on the mass of individual atoms are added multiplies with the number of individual atoms present.

Calculating the mass of $Mg(NO_3)_2$ :

Mass of magnesium = 24.305 g/mol

Mas of nitrogen = 14.007 g/mol

Mass of oxygen = 15.999 g/mol

Mass of $Mg(NO_3)_2=[24.305+(2\times 14.007)+(6\times 15.999)]=148.33g/mol$

1 mole of magnesium nitrate has a mass of 148.33 grams.

Hence, the correct answer is 148.33 grams.

Gekata [30.6K]3 years ago

3 0

Molecular Weight (MW) is the sum of the atomic weights/masses (AM) of every atom in a compound or molecule. Thus, we would add the AM of Mg + 2×[N+(O×3)]:
Mg = 24.31
N = 14.01
O = 16
So we have: Mg + 2×[N+(O×3)] = 24.31 + 2×[14.01+(16×3)] = 24.31+2×[14.01+48] = 24.31+ 2×62.01 = 24.31+124.02 = 148.33

C) is the correct answer

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that's the correct answer

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Answer:

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Explanation:

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We will use this principle to solve our problem.

In our case, the given ions are:

N⁻³ : Z = 7, e⁻ = 10
O⁻²: Z= 8, e⁻ =10
F⁻: Z = 9, e⁻ = 10
Na⁺: Z= 11, e⁻ = 10
Mg⁺²: Z=12, e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

Hence the decreasing order of ionic radius is:

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²

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