I think the best answer would be D. Dolphin!
Answer: 1560632 joules
Explanation:
The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Given that:
Q = ?
Mass of frozen water (ice) = 1kg
C = 4184 J/(kg K)
Φ = (Final temperature - Initial temperature)
= 100°C - 0°C = 100°C
Convert 100°C to Kelvin
(100°C + 273) = 373K
Then, Q = MCΦ
Q = 1kg x 4184 J/(kg K) x 373K
Q = 1560632 joules
Thus, the change in thermal energy is 1560632 joules
According to the table, I, LIBr releases energy as it dissolves.
<span>Lithium bromide is a synthesized compound of lithium and bromine. Its ultimate hygroscopic quality makes LiBr serviceable.</span>
= 3.14 × 10 with the power of 0
(scientific notation)
= 3.14e0
(scientific e notation)
= 3.14 × 100
(engineering notation)
(one)
= 3.14
(real number)
