Answer:
When 2.04g of lead is heat from 104 Kelvin to 204 Kelvin, there is 26.112 Joule generated.
Explanation:
<u>Step 1</u>: Data given
2.04 grams of lead changes from 104 to 204 Kelvin
<u>Step 2</u>: Calculate the generated heat
Q = m*c*ΔT
with Q = Heat energy (in Joules)
with m = mass of a substance (kg)
with c = specific heat (in J/g*K)
with ΔT = Change in temperature = T2 - T1
In this case we have
Q = TO BE DETERMINED
m = 2.04 grams
c = specific heat of lead = 0.128J/ g*K
ΔT = 204 Kelvin - 104 Kelvin = 100
Q = 2.04g * 0.128 J/g*K * 100 K = 26.112 J
When 2.04g of lead is heat from 104 Kelvin to 204 Kelvin, there is 26.112 Joule generated.
