Question

Tim wrote the expressions g^2-2gh-h^2 and -g(g+2h-1) -h^2. He substituted 0 for g and 1 for h, and said the expressions are equivalent. Is he correct? Explain.

Answer 1

Answer

Yes. The result both gives -1.

Step-by-step explanation:

The expressions are $g^2-2gh-h^2$ and $-g(g+2h-1) -h^2$

If he substituted  g=0 and h=1

$g^2-2gh-h^2=0^2-(2X0X1)-1^2=0-0-1=-1$

$-g(g+2h-1) -h^2=-0(0+(2X1)-1)-1^2=0-1=-1$

$-1^2=-1 and 0X a=0$

The result both gives -1.