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Taya2010 [7]
3 years ago
7

Find the area of the given triangles.

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0

154 yd ²

the formula is (b • h) / 2 = A

so plug it in (14 • 22) / 2 = 154

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(x + 1 - 32x^2) + (8x + 21x^2 - 1)
Paladinen [302]

Answer:

-11x^2+9x

Step-by-step explanation: I am assuming you want to simply the problem so I did it for you!

5 0
3 years ago
X^2+4x=-3<br>what would be the steps to find the answer of this equation?<br><br>to find x
Verizon [17]
X^2+4x=-3
x^2+4x+3=0
(x+1)(x+3)=0
x+1=0 so x=-1
x+3=0 so x=-3
so the solution is x=-3,-1
Hope this helped! Please rate my answer if I helped you! Any questions please feel free to ask! Thank you so much!
7 0
3 years ago
What is the factor for 30n-40
nikitadnepr [17]
Factor: 
<span>30n - 40 = 10(3n - 4)

hope it helps</span>
7 0
3 years ago
Can you solve 4 + 2/3 x = -5 in fraction form?
guapka [62]

Answer:

\frac{-27}{2} = (-13)(\frac{1}{2})

Step-by-step explanation:

The given equation is 4 + 2/3 x = -5

Taking variable on one side and constants on other side, we get

-9 = (\frac{2}{3})(x)

x = (\frac{3}{2})(-9) = \frac{-27}{2} = (-13)(\frac{1}{2}) = -13.5

The number in decimal form is given by -13.5

The number in fraction form is given as \frac{-27}{2} = (-13)(\frac{1}{2})

3 0
3 years ago
A standard brick is 3.625 inches wide, 2.25 inches high, and 7.625 inches long. How many bricks could be in a pallet of bricks t
Snezhnost [94]

Answer: Option D. 1,778

Solution:

Standard brick:

Width: w=3.625 in

Height: h=2.25 in

Length: l=7.625 in

Volumen of one standard brick: v

v=w*h*l

v=(3.625 in)*(2.25 in)*(7.625 in)

v=62.19140625 in^3

Pallet of bricks:

Side: s=4 feet

s=(4 feet)*(12 in / 1 feet)→s=48 in

Volume of a pallet of bricks: V=s^3

V=(48 in)^3

V=110,592 in^3

Number of bricks could be in  a pallet: n

n=V/v

n=(110,592 in^3) / (62.19140625 in^3)

n=1,778.252119

n=1,778

6 0
3 years ago
Read 2 more answers
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