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Nikitich [7]
3 years ago
11

In ​ kite PQRS ​, TS=6 cm and TP=8 cm

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0

Answer: the answer to thia problem is 10 i hope it helps


Step-by-step explanation:


asambeis [7]3 years ago
6 0
PQ=17
RS=14


hope it help
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Anyone know this????
Jet001 [13]

Answer:

last one

Step-by-step explanation:

because it's correct

3 0
2 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
1 year ago
You roll a 6-sided die two times.<br> What is the probability of rolling a 2 and then rolling a 3?
docker41 [41]

Answer:

The answer is 1/3 or 4 out 12

Step-by-step explanation:

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3 years ago
Read 2 more answers
Find each variable please!!!
elena-14-01-66 [18.8K]

Answer:

x = 6.5

Step-by-step explanation:

By property of intersecting secants outside of circle.

6(6 + x) = 5(5 + 10) \\  36 + 6x = 5 \times 15 \\ 6x = 75 - 36 \\ 6x = 39 \\ x =  \frac{39}{6}  \\ x =  \frac{13}{2}  \\ x = 6.5

8 0
3 years ago
Do number 4 a please thank you
brilliants [131]
Answer for 4a. 25(n + 6)

Reason

The product (means to multiply)
Six more than a number (n + 6)
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Expression is 25(n+ 6)
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11 months ago
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