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Nikitich [7]
3 years ago
11

In ​ kite PQRS ​, TS=6 cm and TP=8 cm

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0

Answer: the answer to thia problem is 10 i hope it helps


Step-by-step explanation:


asambeis [7]3 years ago
6 0
PQ=17
RS=14


hope it help
You might be interested in
Can someone please help me with this question?
liq [111]
To get the solution we are looking for we need to point out what we know.
1. We assume that 55 is 100% because its the output value of the task.
2. We assume that the x is the value we are looking for. 
3. If 100% = 55 so we can write it down as 100%=55 
4. We know that x% = 44 of the output value so we can write it as x%=44.
5. Now we have two simple equations: 1) 100%=55 2) x%=44 where left sides of both of them have the same units and both right sides have the same units so we can do something like that 100%/x%=55/44.
6. Now we just have to solve the simple equation and we will get the answer.
7. Solution for 44 is what percent of 55 100%/x%=55/44 (100/x)*x=(55/44)*x we multiply both sides of the equation by x 100= 1.25*x we divide both sides of the equation by (1.25) to get x 100/1.25=x 80=x now we have: 44 is 80% of 55! 

Quick answer = 44 is 80% of 55
Hope this helps! ;D
3 0
3 years ago
Please can someone explain how to work out this
wariber [46]

Answer:

T = 4B + 10C

Step-by-step explanation:

Since there are 4 doughnuts in a bag then there are 4B doughnuts in B bags

Since there are 10 doughnuts in a carton then there are 10C doughnuts in C cartons, thus summing the two quantities gives

T = 4B + 10C

6 0
3 years ago
Simplify then factor
erastova [34]
U.s marine core semper fi
5 0
3 years ago
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
3 years ago
Read 2 more answers
$10000 in an account paying 8% compounded annually. how much will the account be worth in 18 years
lawyer [7]
10000x8%= $800 anually
anually=yearly
800x18=14400

5 0
3 years ago
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