The reflection transformation in the question is a rigid transformation,
therefore, the image and the preimage are congruent.
The statements that are true are;
Reasons:
The given parameter are;
Triangle ΔABC is reflected across the line 2·X, to map onto triangle ΔRST
Required:
To select the true statements
Solution:
A reflection is a rigid transformation, therefore, the distance between corresponding points on the image and the preimage are equal.
Therefore;
AB = RS
BC = ST
AC = RT
Given that the image formed by a reflection is congruent to the preimage, we have;
ΔABC ≅ ΔRST
∠ABC ≅ ∠RST
m∠ABC = m∠RST by the definition of congruency
∠BCA ≅ ∠STR
m∠BCA = m∠STR by the definition of congruency
∠BAC ≅ ∠SRT
m∠BAC = m∠SRT by the definition of congruency
Therefore, the true statements are;
- <u>AB = RS</u>; Image formed by rigid transformation
- <u>∠ABC ~ ∠RST</u>; Definition of similarity
- <u>ΔABC = ΔRST</u>; By definition of congruency
- <u>m∠BAC = m∠SRT</u>; by the definition of congruency
Learn more here:
brainly.com/question/11787764
Do the 11% off first.
11% of 52$ is 46.38$, then you take $40 off and your total is only $6.38
if you do -40$ first then you have $12 left and 11% off that is $10.68.
To solve this question, you would need to find the common denominator among the 2 fractions. In this case it would be
72.
Then multiply numbers to both of the fractions to get to the bottom number in both fractions equaling 72.
40/72 + 27/72 =67/72.
Try to reduce to lowest terms by dividing a common number from both of them if possible.
2x + y = 10
2x + 3y = 22
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