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svp [43]
4 years ago
9

The graph of f(x)=x^2 is shown.

Mathematics
2 answers:
lara [203]4 years ago
7 0

I got question 3 wrong, but it still shows the correct answer. If these answers get you a 100, friend me.

Gekata [30.6K]4 years ago
6 0
<span>The equation given is f(x) = x^2 - 12x + 27
</span>
Based on its form, it is a parabola. First, factor the quadratic equation:

f(x) = (x-9) (x-3)

Plot in the x-y plane, assign values of x and solve for the values of y. 

x       y
1       16
2      7
3      0
0      27
-1     40
-2    55     
<span>-3    72 </span>
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For a quadratic of the form f(x)=ax^2+bx+c, we have the quadratic formula 
x=\dfrac{-b \pm \sqrt{b^2 -4ac}  }{2a},
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So, given 2x^2-16x+27=0, we can get that a=2, \ b=-16, and c=27. We substitute these numbers into the quadratic formula above.

x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}

x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}

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This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the \pm symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.
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Please help me to solve
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90-80=10. 9-6=1 and 0-0=0 so it equals 10. Hopefully this helped!! =“)
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Malik’s solution to the equation , when , is shown below.
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