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Snezhnost [94]
3 years ago
15

Which amount is largest? 1kg 1dg 100g 1000mg

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
6 0

Answer: The largest one is 1kg

Step-by-step explanation:

Paul [167]3 years ago
5 0

Answer:

your answer would be 1kg

Step-by-step explanation:

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Which equation represents the magnitude of an
Basile [38]

Answer:

M=\log{(100S)}

Step-by-step explanation:

The <em>Richter scale</em>, the standard measure of earthquake intensity, is a <em>logarithmic scale</em>, specifically logarithmic <em>base 10</em>. This means that every time you go up 1 on the Richter scale, you get an earthquake that's 10 times as powerful (a 2.0 is 10x stronger than a 1.0, a 3.0 is 10x stronger than a 2.0, etc.).

How do we compare two earthquake's intensities then? As a measure of raw intensity, let's call a "standard earthquake" S. What's the magnitude of this earthquake? The magnitude is whatever <em>power of 10</em> S corresponds to; to write this relationship as an equation, we can say 10^m=S, which we can rewrite in logarithmic form as m=\log{S}.

We're looking for the magnitude M of an earthquake 100 times larger than S, so reflect this, we can simply replace S with 100S, giving us the equation

M=\log{(100S)}.

To check to see if this equation is right, let's say we have an earthquake measuring a 3.0 on the Richter scale, so 3=\log{S}. Since taking 100 times some intensity is the same as taking 10 times that intensity twice, we'd expect that more intense earthquake to be a 5.0. We can expand the equation M=\log{(100S)} using the product rule for logarithms to get the equation

M=\log{(100S)}=\log{100}+\log{S}

And using the fact that \log{100}=2 and our assumption that \log{S}=3, we see that M=2+3=5 as we wanted.

3 0
4 years ago
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Answer:

A.  

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Step-by-step explanation:

I think you need to double the area of the scaled factor.

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