X = short section of rope
4x = longer section of rope
x + 4x = 25
5x = 25
x = 5
…or in other words the shorter piece of rope is 5 feet long
To find the slope of the line we can use the following formula:

1 - (-3)/5 - 1
4 / 4
1
<h3>The slope of the line is equal to 1.</h3>
To find the equation, we can just use slope-intercept form.
We already know the slope, so our current equation is y = x
By knowing the slope, we can apply the slope to our lowest pair of coordinates to find the y value when x = 0.
Subtract 1 from the x and y values of (1, -3)
(0, -4) is our new point, and so we know the y-intercept is -4.
<h3>Our equation for the line is y = x - 4</h3>
Two or more angles whose sum is 180° are called supplementary angles. The measure of the ∠y is 120°.
<h3>What are supplementary angles?</h3>
Two or more angles whose sum is 180° are called supplementary angles. If a straight line is intersected by a line, then there are two angles form on each of the sides of the considered straight line. Those two-two angles are two pairs of supplementary angles. That means, that if supplementary angles are aligned adjacent to each other, their exterior sides will make a straight line.
Given the puck strikes the wall at an angle of 30°, it goes away at the same angle of 30°. Therefore, the measure of angle y can be found using the sum of the angle as a supplementary angle. Thus, we can write,
30° + ∠y + 30° = 180°
60° + ∠y = 180°
∠y = 180° - 60° = 120°
Hence, the measure of the ∠y is 120°.
Learn more about Supplementary Angles:
brainly.com/question/2882938
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Answer:
y = -2x -3
Step-by-step explanation:
The line crosses the y-axis at -3, so that is the y-intercept.
It has a "rise" of -2 units for each "run" of 1 unit, so the slope is -2. (For example, from point (-1, -1) to point (0, -3).)
The slope m and y-intercept b are used in the slope-intercept form of the equation of a line:
y = mx + b
For the values this line has, the equation is ...
y = -2x -3
Part A:5=2x^2-x^2+13
5=x^2+13
0=x^2+13-5
0=x^2+8
Part B:5=2x^3-x^3+13
5=x^3+13
0=x^3+13-5
0=x^3+8