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7nadin3 [17]
2 years ago
15

mary has 3 blouses (red, black, and white), 2 pairs of pants (black and blue), and 4 pairs of shoes ( red, blue, black, and whit

e). if mary picks each part of her outfit randomly, what is the probability that mary's outfit will be black bouse, black pants, black shoes?
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
4 0

The probability that Mary's outfit will be black blouse, black pants, black shoes is 1/24 if the Mary has 3 blouses, 2 pairs of pants, and 4 pairs of shoes.

<h3>What is probability?</h3>

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words the probability is the number that shows the happening of the event.

We have:

Mary has 3 blouses (red, black, and white), 2 pairs of pants (black and blue), and 4 pairs of shoes (red, blue, black, and white).

P(black blouse) = 1/3

P(black pants) = 1/2

P(black shoes) = 1/4

Probability that Mary's outfit will be black blouse, black pants, black shoes:

= (1/3)(1/2)(1/4)

= 1/24

Thus, the probability that Mary's outfit will be black blouse, black pants, black shoes is 1/24 if the Mary has 3 blouses, 2 pairs of pants, and 4 pairs of shoes.

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

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A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c
Alenkinab [10]

Answer:

C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

l\times b\times h

where l is the length, b is the base and h is the height.

Volume of box =

s^2h = 150\\\\h = \dfrac{150}{s^2}

Area of base =

\text{side}\times \text{side} = s^2

Cost of concrete for the base = $4

Cost of base($) = 4s^2

Area of roof =

\text{side}\times \text{side} = s^2

Cost of material for the roof = $2

Cost of roof ($) = 2s^2

Area of 4 walls =

4\times (sh)\\=4sh

Cost of material for the side = $2.50

Cost of material of side($) =

2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}

is the required cost function.

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Step-by-step explanation:

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