An earthquake causes a 3 kg book to fall from a shelf. If the book lands with a speed of 4.0 m/s, from what height did it fall?
1 answer:
Given: 3kg book speed of falling of 4.0 m/s acceleration due to gravity -9.8 m/s² Vf² = Vi² + 2 * a * d Vf = final velocity ; Vi = initial velocity ; a = acceleration ; d = distance 0² = (4 m/s)² + 2(-9.8m/s²) * d 0 = 16 m²/s² -19.6 m/s² * d -16 m²/s² = -19.6 m/s² * d -16 m²/s² / -19.6 m/s² = d 0.82 m = distance The 3 kg book fell from the a shelf at the height of 0.82 meters.
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