Question

Please answer this for me

Answer 1

1. substitution....because it would be easier to just sub one y in for the other then it would be to use the elimination method

2. substitution....because in one of the equations, u already have y...so just sub 6x - 13 in for y in the other equation

3. elimination....all u have to do is add them and ur y terms are eliminated, allowing u to find x

4. substitution....sub in x + 1 for y in the other equation
     2x + 4(x + 1) = 28          y = x + 1
     2x + 4x + 4 = 28             y = 4 + 1
     6x = 24                           y = 5
     x = 4
the solution for this system is : (4,5)

5. elimination..
    3x - y = -1                        3(-2) - y = -1
    2x + y = -9                        -6 - y = -1
  ------------------add                -y = -1 + 6
   5x = -10                              -y = 5
    x = -2                                  y = -5
the solution to this system is : (-2,-5)

6. substitution.....sub in one y for the other
    2/3x - 1 = -x + 4              y = -x + 4
    2/3x + x = 4 + 1              y = -3 + 4
    5/3x = 5                          y = 1
    x = 5 * 3/5
    x = 3
so the solution to this system is (3,1)

7. substitution...sub one y in for the other
    296 - 10x = 200 + 6x                y = 200 + 6(6)
    296 - 200 = 6x + 10x                y = 200 + 36
    96 = 16x                                   y = 236
    6 = x
so the solution for this system is (6,236)