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Ivenika [448]
4 years ago
11

F(2) = 20 and f(3) = 12

Mathematics
1 answer:
Illusion [34]4 years ago
8 0

Answer: 10(2)=20 and 4(3)=12

Step-by-step explanation:

1) Divide 20 by 2 which would be 10 that gives you the sum of F

2) Divide 12 by 3 which is equals 4 so thats the sum of F for f(3)=12

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A(t) = (t – k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.
mr Goodwill [35]

the absolute value of the product of the zeros of a is -108 .

<u>Step-by-step explanation:</u>

Here we have , a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.  Given that a(2) = 0 . We need to find the  absolute value of the product of the zeros of a . Let's find out:

Equation every factor of a(t) to zero we get:

⇒ a(t) = (t - k)(t - 3)(t - 6)(t + 3) = 0

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⇒ k(3)(6)(-3)

⇒ 2(3)(6)(-3)

⇒ -108

Therefore, the absolute value of the product of the zeros of a is -108 .

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