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2 years ago

11

Siblings Brandon Brooke truant and Trisha owe there parents 100$ write a number sentence to show how much each sibling owes if t

hey share the debt equally

1 answer:

Fynjy0 [20]2 years ago

3 0

Answer:

25?

Step-by-step explanation:

100/ 4=25

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You buy a calculator for $65. A 6% sales tax is added.

Vika [28.1K]

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2 years ago

Write the formula for an exponential function with initial value 300 and decay factor 0.73

postnew [5]

Answer: 300*0.73^x

Step-by-step explanation:

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2 years ago

II.) Simplify the following by applying the laws of indices.

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2 years ago

G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d

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By definition of covariance,

$\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]$

$\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]$

We have

$\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]$

$=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

$\mathbb E[aX-b]=a\mathbb E[X]-b$

$\mathbb E[cY-d]=c\mathbb E[Y]-d$

$\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

Putting everything together, we find the covariance reduces to

$\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)$

as desired.

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2 years ago

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vivado [14]

It should be A
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3 years ago

Read 2 more answers