Answer:
The smaller number is 0.6666... repeating, and the larger number is 1.3333... repeating.
Step-by-step explanation:
Answer:
Step-by-step explanation:
There are
2 yellow
3 magenta
5 blue
marbles in the bag.
So total of 2 + 3 + 5 = 10 marbles
We have to multiply the probability of yellow on first pick by the probability of yellow on second pick (WITHOUT REPLACEMENT).
We denote P(Y1) as probability of yellow on first draw &
P(Y2) as probability of yellow on second draw
Thus,
P(Y1) = 2/10 = 1/5 [since 2 yellow and 10 total marbles]
Now,
P(Y2) = 1/9 [since now 1 yellow is taken out and NOT replaced, so we have 1 yellow remaining and total 9 marbles]
Now, we multiply:
P(Y1) * P(Y2) = 1/5 * 1/9 = 1/45
The probability is
The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
Step-by-step explanation:
2008because there is no difference between the number of sold notebooks
1.
no, there will never be a negative y-value. <span>y= |x| will always be nonnegative. |x| can be distance x is from 0 and a distance can never be negative.
</span>2.
you can define it as
y = |x| = x if x ≥ 0, -x if x < 0
absolute value can be
interpreted as a function that does not allow negative real numbers,
forcing them to be positive (leaving 0 alone). if the input x is more
than or equal 0, then x stays positive so there is no need to do
anything: "x if x ≥ 0".
if the input is less than 0, then it is an
negative number and needs a negative coefficient to negate the negative:
"-x if x < 0"
example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does
if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.
for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
