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kati45 [8]
4 years ago
8

Can someone help me please?

Mathematics
1 answer:
4vir4ik [10]4 years ago
5 0
Q1. Find the horizontal & verticle distance between points AB & find 2/3 of the verticle distance and 2/3 of the horizontal distance and add these onto the co-ordinates of point A to find the co-ordinates of point M
Q2 is C

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amid [387]

Answer:

A) True

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C) True

D) Not sure

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3 years ago
Justin calculates the perimeter of a rectangle with a length of 2x-3 and width
n200080 [17]

Answer:

No

Step-by-step explanation:

No, because the perimeter of a rectangle is 2(x+y). Justin added the sides. Then he should have multiplied by 2 but he didn't so Justin is incorrect.    

Hope this helps plz mark brainliest :D

5 0
3 years ago
Read 2 more answers
Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive
PtichkaEL [24]
Looks like the PMF is supposed to be

\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65

Next,

\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25

\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5

\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2
\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5
\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}

If Y=X^2+1, then X^2=Y-1\implies X=\sqrt{Y-1}, where we take the positive root because we know X can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that Y can take on the values 1^2+1=2, 2^2+1=5, and 5^2+1=26. At these values of Y, we would have the same probability as we did for the respective value of X. That is,

\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}

Part (5) is incomplete, so I'll stop here.
8 0
4 years ago
Marlon and Clint went to the movies.if they each bought cookies for 9.25 and a soda for. 6.55 what was their total bill after ad
klasskru [66]

Answer:

$38.72

Step-by-step explanation:

this is for 8.75% sales tax which is what I would think it would be as $8.75 extra as tax is ridiculous on something this small

6 0
3 years ago
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James is 1 3/7 times as tall as his brother hois brother is 3 1/2 feet tall
Zepler [3.9K]
James is 5 feet tall.
4 0
4 years ago
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