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Nuetrik [128]
4 years ago
5

Simplify the expression where possible. (t^9)^-8

Mathematics
1 answer:
tankabanditka [31]4 years ago
7 0

( {t}^{9} ) {}^{ - 8}  \\  = t {}^{9 \times ( - 8)}  \\  =  {t}^{ - 72}

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Larry drew a circle with a circumference of 40.82 centimeters. What is the area of the circle? Use 3.14 for π.
Jlenok [28]

Answer:

1308.02cm^2

Step-by-step explanation:

Finding Radius = D/2

40.82/2 = 20.41 centimetres

Finding Area of a circle

E =  πr^2

= 3.14 x 20.41^2

= 416.57 π

= π x 416.5681 =  1308.02cm^2

3 0
3 years ago
Read 2 more answers
What's the surface area of a sphere with radius 5 centimeters
torisob [31]
Surface area: 4*pi*r^2 = 4*pi*5^2= 4*25*pi = 100pi or <span>314.16</span>
3 0
3 years ago
A taxi charges a flat fee of 4.00 plus 2.25 per mile. How much will the taxi driver earn if he takes one passenger 4.8 miles and
nydimaria [60]
Write an equation.
T = Total money made
M = miles driven
4 + 2.25m 
T = 7.3*2.25 + 4 + 2.25*4.8 + 4 
T = 8 + 7.3*2.25 + 2.25 * 4.8
4.8 * 2.25 = 10.8
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T = 16.425 + 8 + 10.8
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So, the total amount of money he made was $35.25.
6 0
3 years ago
The areas of two similar triangles are 49 cm2 and 16 cm2. what is the ratio of the corresponding side lengths? of the perimeters
Nikitich [7]
We know that

[area of larger triangle]=[scale factor]²*[area of smaller triangle]
[scale factor]=√[area of larger triangle/area of smaller triangle]
[scale factor]=√[49/16]-----> 7/4

Part A) <span>what is the ratio of the corresponding side lengths?
the ratio </span>of the corresponding side lengths is equals to the scale factor

the answer Part A) is 
the ratio of the corresponding side lengths is 7/4

part B)what is the ratio of the perimeters?
 the ratio of the perimeters is equals to the scale factor

the answer Part B) is 
the ratio of the perimeters is 7/4
4 0
3 years ago
Suppose you are running a racing tournament with 12 horses. All eligible horses run in the race at once, and after the first rac
borishaifa [10]

Answer:

a)  66

b)  45

Step-by-step explanation:

We have 12 horses and after the first race 2 of them have to be eliminated

that condition is equal to consider that 10 horses will be available for the second race.

The number of possiblities we have for the first race is the combination of 12 horses in group of 10

C¹²₁₀   =  12!/ (2!)* (12-2)!   =  12*11/2   = 66

For the second race

C¹⁰₈  = 10! / 8! * (10-8)!   =   10*9/ 2   = 45

4 0
3 years ago
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