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solmaris [256]
3 years ago
11

A country's population in 1995 was 65 million. In 1998 it was 69 million. Estimate the population in 2006 using the exponential

growth formula. Round your answer to the nearest million.
Mathematics
2 answers:
Sidana [21]3 years ago
6 0
Hello,

year x y
1995 0 65
1998 3 69
2006 11 ?

y=b*e^(ax)

if x=0 then y=65 ==>65=b*e^0==>b=65

if x=3 then y=69 ==>69=65*e^(3a)
==>e^(3a)=69/65
==>3a=ln(69/65)
==>a= ln (69/65) /3
==>a=0,019906411...

if x=11 then y=65*e^(0.019906411...*11)
==>y=80,911648...≈81 (millions)



LenKa [72]3 years ago
3 0
80 million. 2001= 73 million. 2004=77 billion. 2007=81 million. Take away a year, maybe take away one million.
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Answer:

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Step-by-step explanation:

(F,Y) = (63,21)

Y3=F so F/3=y

so

F= 40

Y=?

40/3=Y

40/3=13.3

4 0
3 years ago
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Combine the like terms to create an equivalent expression:<br> \large{-2k-(-5)+1}−2k−(−5)+1
Elenna [48]

Answer:

The answer is

- 2x + 5 + 1 - 2x + 5 + 1 =  \\  - 4x + 12 =  \\  - 4(x - 3)

4 0
3 years ago
Differentiate 3x-5/x²-4x​
PolarNik [594]

I assume you mean (3x - 5)/(x² - 4x).

Using the quotient rule, the derivative would be

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7 0
3 years ago
The angle measurements in the diagram are represented by the following expressions.
V125BC [204]

Answer:

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Step-by-step explanation:

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plugging the values

7x + 24 = 3x + 92

Move variable to L.H.S and change its sign

7x - 3x + 24 = 92

Move constant to R.H.S and change its sign

7x - 3x = 92 - 24

Calculate

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Divide both sides of the equation by 4

\frac{4x}{4}  =  \frac{68}{4}

Calculate

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7 0
3 years ago
TV
Pavel [41]

Answer:

Step-by-step explanation:

Model of the frog jump is

h = -6t² + 6t

When will the frog be on the ground? The frog will be on the ground at h=0

Therefore,

0 = -6t² + 6t

Divide through by 6

0 = -t² + t

0 = t(-t + 1)

So, t = 0 OR. 0 = -t + 1

So, t = 0. OR. t = 1

So, we should note that, at t = 0, was when he wanted to lift of from the ground... So, t = 0 will be discarded

So, at t = 1 is when the frog is back to the ground.

It is like it starts from the ground at the 0 seconds and get backs to the ground at 1 seconds

I hope this helps!!!

3 0
4 years ago
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