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3 years ago

How do i find the mean of a group of number's

Mathematics

2 answers:

kondor19780726 [428]3 years ago

7 0

Answer:

Step-by-step explanation:

The mean of a group of numbers is determined by adding all numbers together and then divided the sum by the total number of numbers.

For example: the mean of 1, 19, 100 = (1+19+100)/3 = 120/3 = 40

inna [77]3 years ago

5 0

Lets say your numbers are these...

10,20,30,40,50,60,70,80,90 and 100

you would add those to get 650

Now how many numbers did you add?

You added 10

so now divided

650 by 10

you get 65

that is the mean of those numbers!

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Please help solve much appreciated

DIA [1.3K]

Step-by-step explanation:

For the Cuboid, the formula will be:

Width x Height x Length

For the cylinder the volume formula will be:

$\pi \: \times \: {radius}^{2} \times \: length$

7 0

3 years ago

Please help me, question is the picture

Hitman42 [59]

The answer is 425 miles.

Both of the companies can be represented by an equation. The first company being f(a) and the second company bring f(b).
f(a)=$0.06x+65
f(b)=$0.10x+48
We want to find where they are equal, so we can set the equations equal to each other.
$0.06x+65=$0.10x+48
From here we can simplify the equation.
17=$0.04x
425=x

8 0

3 years ago

Read 2 more answers

Given that x square + 5 x + c is a perfect square find the value of C

lawyer [7]

Answer:

c = $\frac{25}{4}$

Step-by-step explanation:

To make a perfect square

add ( half the coefficient of the x- term )² to x² + 5x

x² + 5x + ( $\frac{5}{2}$ )²

= x² + 5x + $\frac{25}{4}$

= (x + $\frac{5}{2}$ )² ← a perfect square

5 0

3 years ago

Write a equation for y=|x| if the graph is translated right by 3 units and down by 1 unit

Leni [432]

Answer:

y=|x -3| -1

Step-by-step explanation:

4 0

3 years ago

find the formula for a rational function that satisfies all of the following. its x-intercept is (-3,0). it has a vertical asymp

Norma-Jean [14]

Let that be

$\\ \rm\Rightarrow y=\dfrac{a(f(x))}{g(x)}$

Two vertical asymptotes at -1 and 0

$\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x(x+1)}$

If we simply

$\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x^2+1}$

Denominator has degree 2
Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
But there should be a x intercept at -3 so one zeros should be -3

Find a equation

3x²+9x

Find zeros

3x²+9x=0
3x(x+3)=0
x=0,-3

Horizontal asymptote

3x²/x²
3

So our equation is

$\\ \rm\Rightarrow y=\dfrac{3x^2+9x}{x(x+1)}$

Graph attached

4 0

2 years ago