Answer:
<h2>
![7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x](https://tex.z-dn.net/?f=7%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206x)
</h2>
Solution,
![7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\ = 7 \sqrt[3]{2x} - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x} - 3 \times \sqrt[3]{2 \times 2 \times 2x} \\ = 7 \sqrt[3]{2x} - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 3 \times 2 \times \sqrt[3]{2x} - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x](https://tex.z-dn.net/?f=7%28%20%5Csqrt%5B3%5D%7B2x%7D%20%29%20-%203%28%20%5Csqrt%5B3%5D%7B16x%7D%20%29%20-%203%28%20%5Csqrt%5B3%5D%7B8x%7D%20%29%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%20%28%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202x%7D%20%20-%203%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202x%7D%20%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%20%282%20%5Csqrt%5B3%5D%7B2%7D%20x%29%20-%203%20%5Ctimes%202x%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%202%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%202x%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206x)
Hope this helps...
Good luck on your assignment...
Answer:
50
Step-by-step explanation:
Let the numbers be 3x, 4x, 5x
(3x)^3 + (4x)^3 + (5x)^3 = 216000
27x^3 + 64x^3 + 125x^3 = 216000
216x^3 = 216000
x^3 = 1000
x = 10
5x = 5(10) = 50
Answer: 50
Answer:
<h2>A. x = 1</h2>
Step-by-step explanation:

If there are 2 variables<span> and they are I(1) then u </span>can<span> apply enger and granger ... Recently I came across the 1st </span>difference<span> OLS model in a thesis
hope this helps!</span>