Let the lengths of EH and FG = x
Let the lengths of EF and HG = x-5
Solve,
X + X + (X-5) + (X-5) = 48
4X - 10 = 48
4X = 58
X = 14.5
EH= 14.5
FG = 14.5
EF = 9.5
HG = 9.5
F(x) = x^2 + 2x -1
Domain all real number
Range: all real numbers equal or greater than -2.
To find the range you need to find the vertex of the parabole, which is (-1,-2) and use the fact that, given that the coefficient of x^2 is positive, the funcion open upwards (which means that the vertex is a global minimum).
To find the vertex you use the quadratic formula to find the roots and then the x-coordinate of the vertex is in the middle of the two roots.
Answer:
just do it by Pythagoras theoram
Step-by-step explanation:
because it is a right angle
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