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kirza4 [7]
3 years ago
13

Match the range of the function f(x) = x2 2x − 1 to its domain.

Mathematics
1 answer:
Ivan3 years ago
7 0
F(x) = x^2 + 2x -1

Domain all real number

Range: all real numbers equal or greater than -2.

To find the range you need to find the vertex of the parabole, which is (-1,-2) and use the fact that, given that the coefficient of x^2 is positive, the funcion open upwards (which means that the vertex is a global minimum).

To find the vertex you use the quadratic formula to find the roots and then the x-coordinate of the vertex is in the middle of the two roots.
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the coordinates of the endpoints of AB are A (-8, -2) and B(16,6). Point P is on AB what are the coordinates of point P such tha
garri49 [273]
We have that
<span>A (-8, -2) and B(16,6)

step 1
find the distance AB in the x coordinates
dABx=(16-(-8))-----> 24 units

step 2
find coordinate x of P (Px)
Px=Ax+(3/5)*dABx------> Px=(-8)+(3/5)*24----> 6.4

step 3
F</span>ind the distance AB in the y coordinates
dABy=(6-(-2))-----> 8 units

step 4
find coordinate y of P (Py)
Py=Ay+(3/5)*dABy------> Py=(-2)+(3/5)*8----> 2.8

the coordinates of P are (6.4,2.8)

see the attached figure

6 0
3 years ago
3x-4y=11 <br>3x+2y=2<br>please help, I need to find what the answer is for x and y​
Zielflug [23.3K]

Answer:

I have attached a picture of me solving the equation.

Now you must be wondering how I got the answer, well first simplify the expression in y = mx + b. Then graph it on demos. Do the same thing for the other expression. Pick any point that lies on the line. That is your solution to the equation.

The green line is the expression of 3x - 4y = 11. I simplify the equation in y = mx + b giving me y = 3/4x - 11/4.

The orange line is the expression of 3x + 2y = 2. I simplify the equation in y = mx + b giving me y = -3/2x + 1.

Hope this helps, thank you !!

3 0
3 years ago
.Choose the equation that represents the line that passes through the point (−1, 6) and has a slope of −3.
leonid [27]
Y=-3+3 answer do I need to explain?
5 0
2 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
I'll give 20 points
Naddik [55]

it is 3 because if it has infinte solutions than it is = to 0 and 1 and infinite solutions

8 0
3 years ago
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