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kicyunya [14]
3 years ago
6

The perimeter of a parallelogram EFGH is 48 in. If EF is 5 in les than EH, find the lengths of all four sides

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0
Let the lengths of EH and FG = x
Let the lengths of EF and HG = x-5
Solve,
X + X + (X-5) + (X-5) = 48
4X - 10 = 48
4X = 58
X = 14.5
EH= 14.5
FG = 14.5
EF = 9.5
HG = 9.5
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4 years ago
Which of the following are solutions to the equation below?
scoundrel [369]

Answer:

The correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

Step-by-step explanation:

Given the expression

x^2+10x+25=8

Subtract 25 from both sides

x^2+10x+25-25=8-25

Simplify

x^2+10x=-17

Add 25 or 5² to both sides

x^2+10x+5^2=8

as

x^2+10x+5^2=\left(x+5\right)^2

so the expression becomes

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\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{8}

Subtract 5 from both sides

x+5-5=2\sqrt{2}-5

x=2\sqrt{2}-5

solve

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Subtract 5 from both sides

x+5-5=-2\sqrt{2}-5

x=-2\sqrt{2}-5

Therefore, the solution to the equation

x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5

Hence, the correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

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Hey there!

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