Can someone help me please!.

Let I (x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"

FrozenT [24]

Answer:

Step-by-step explanation:

L(x) means that Student X has an internet connection

C(x,y) means that students X and Y have chatted over the internet

The domain for variables X and Y comprise all students in your class. We now use quantifiers or algebraic functions to express each of the statements:

(A) Jerry does not have an internet connection

L(x) = 0

Where X represents Jerry

(B) Rachel has not chatted over the internet with Chelsea

C(x,y) = 0

Where X and Y represent Rachel and Chelsea

(C) Jan and Sharon have never chatted over the internet

L(x) + L(y) = 0

Where X and Y represent Jan and Sharon. If they have NEVER chatted over (the question didn't say they have never "with each other", it says they have never chatted at all) the internet, then they've probably never had an internet connection!

(D) No one in the class has chatted with Bob

Let Y represent Bob and X1, X2, ..., Xn represent everyone else in the class.

The value of Y is not significant here (because it is raised to the power of zero and that makes it equal to 1 and when 1 is multiplied by any X value, the X value or student remains the same) but we have to put it, to represent Bob.

The quantifier here is C (X1Y°, X2Y°, X3Y°, ..., XnY°)

5 0

3 years ago

a teacher plans a simulation to estimate the probability that a student will pick a vowel out of a bag of 26 tiles, each with a

Alex Ar [27]

Answer:

Yes

Step-by-step explanation:

Given that a teacher prepares 26 tiles with 5 vowels numbered 1 and 21 consonants numbered 2.

The probability for drawing vowel = $\frac{5}{26}$