5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
If you need any steps explained lmk
If this is a True or False question, that is true.
Answer:
3) 27 cubed
4) 72 cubed
5) 125 cubed
8) 27 cubed. 3 is the length, 3 is the width, and 3 is the height.
9) 72 cubed. 6 is the length, 3 is the width, and 4 is the height.
10) 125 cubed. 5 is the length, 5 is the width, and 5 is the height.
Step-by-step explanation
Here's what to show if your teacher requires for you to show your work.
3) 3 x 3 x 3 = 27
4) 6 x 3 x 4 = 72
5) 5 x 5 x 5 = 125
8) 3 x 3 x 3 = 27
9) 6 x 3 x 4 = 72
10) 5 x 5 x 5 = 125
These are the ones I'd suggest putting the up and down form on.
10) and 5) Also put 5 x 5 = 25. 4) and 9) Also put 6 x 3 = 18.
<em>2 3</em>
25 18
<u>x 5 </u> <u>x 4 </u>
125 72
Hoped this answered everything! Feel free to ask me if there's something I missed! :)
