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3 years ago

Which description best defines FG¯¯¯¯¯ ?

Mathematics

2 answers:

kogti [31]3 years ago

8 0

The answer is A because say there is point H between F and G the point would be considered summarised by F and G

Gwar [14]3 years ago

7 0

Answer:

A. the set of all points between point F and point G, including point F and point G

Step-by-step explanation:

FG is a segment with endpoints at point F and point G.

Line segments contain an infinite number of points; this means this will be the set of all points between F and G, including both F and G.

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(−1) to the power of 3

stiv31 [10]

(-1) ^3

-(1) * (-1) * (-1)

1 * (-1)

=-1

Answer: -1

3 0

2 years ago

Read 2 more answers

test the symmetric of a function f(x)=x5+x3+x plz answer my question and you will be mark as brainly

babunello [35]

Answer:

Step-by-step explanation:

2000264(X) b x a =177777082

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2 years ago

What is 0.644 in expanded form

Brrunno [24]

I hope this helps you

0,644

644/1000

161/250

4 0

2 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$