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Norma-Jean [14]
3 years ago
13

I furniture sales person sells account for $1560 she receives a 2.75% commission on the sale of the cat how much did she earn on

the sale?round your answer to the nearest cent
Mathematics
1 answer:
horrorfan [7]3 years ago
5 0
Just 1560x.0275

$42.90
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Which equation is represented by Ms. Wilson’s model
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<span>                         D                     Q</span>

TC<span> =  D x P <span>+  ___   x  Cp +  ____  x Cs</span></span>

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Given m||n, find the value of x.<br><br> (2x+9)<br> (7X+24)
motikmotik

<em>Given, 9−7x=5−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x⇒x= </em><em>4</em><em>/</em><em>4</em><em> </em><em> =1</em>

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8 0
3 years ago
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

5 0
4 years ago
A recipe for brownies calls for 2/3 Cup of chocolate chips for a batch of two dozen brownies. How many chocolate chips will be n
vovikov84 [41]

Answer:

6 cups

Step-by-step explanation:

(18  \times \frac{2}{3} ) \div 2 =

12 \div 2 =

6

8 0
4 years ago
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