Charlene puts together two isosceles triangles so that they share a base, creating a kite. The legs of the triangles are 10 inch
es and 17 inches, respectively. If the length of the base for both triangles is 16 inches long, what is the length of the kite’s other diagonal?
2 answers:
From the information given you have:
1) Smaller diagonal of the kite: 16 inches
2) Larger diagonal of the kite: height of one triangle (h1) + height of the other triangle (h2)
3) Calculation of the height of the smaller triangle, h1:
10^2 = (16/2)^2 + (h1)^2 => h1 = √ [10^2 - 8^2] = 6
4) Calculation of the height of the larger triangle, h2
17^2 = (16/2)^2 + (h2)^2 => h2 = √[17^2 - 8^2] = 15
5) Larger diagonal = h1 + h2 = 6 + 15 = 21
Answer: 21 inches
Answer:
21 inches
Step-by-step explanation:
You might be interested in
each one gets 2 and their will be 4 slices left
I think it’s 700, but I’m not positive
Answer:
7/10, 3/2, 13/12, 11/24, and 24/35
Answer:
the answers are c, d, &f
Step-by-step explanation:
the equivalence to 12:3
1200:300. = 12:3 (reduce by 100)
12:3= 4:1 (reduce by 3)
24:6= 12:3 (reduce by 2)
Answer:
Each number increases by 3.
