Answer:
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Explanation:
Following are the program in c#
using System; // namespace
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Tasks
{
class Program
2 // program2
{
static void Main(string[] args) // Main function
{
double num = 958254.73789621; // variables
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Console.Read();
}
}
}
Output:
Format Double : 958254.737
Here we have declared a variable num of type double which store the value num=958254.73789621. To do format with the double number i used a syntax {0:n3}. This syntax {0:n3}is separated with :(colon) here 0 represent the value before the decimal point that is 958254 and n3 represent the value upto 3 decimal points. Hence this statement give the output with three digit after the decimal point .
I believe its E she can insert a picture in the text book
Answer:
Cloud
Explanation:
Cloud computing is a central form of storing data on a data center, provided online, to provides inexpensive and secure storage facilities and central accessing of document, using any device and accessing the data from anywhere and time.
Data stored in a clients computer system, would have to be transferred to another remote computer by using a portable storage, to share data. Using a cloud service or a database center service, a document can be accessed by a group of users at the same time, in different places, and assures a secure data in the database.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
This program is written in C++.
#include <iostream>
using namespace std;
int main()
{
string word;// variable for taking user input
int cond;// to set condition true if user preses the stop and exit from loop
cout<<"Enter word: \n";
cin>>word;
do// start while loop
{
if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit
{
cond=0;
}
else//otherwise loop continue
{
cout<<" You Entered "+ word +"\n";
cout<<"Enter word: \n";
cin>>word;
cond=1;
}
}
while(cond == 1);// if user don't enter word "stop" loop run continuesly.
cout<<"Program exit";
return 0;
}
