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ruslelena [56]
3 years ago
7

Write a programme to find the sum of first three cube number?

Computers and Technology
1 answer:
aleksandrvk [35]3 years ago
7 0

// Simple Java program to find sum of series

// with cubes of first n natural numbers

import java.util.*;

import java.lang.*;

class GFG {

/* Returns the sum of series */

public static int sumOfSeries(int n)

{

int sum = 0;

for (int x = 1; x <= n; x++)

sum += x * x * x;

return sum;

}

// Driver Function

public static void main(String[] args)

{

int n = 5;

System.out.println(sumOfSeries(n));

}

}

// Code Contributed by Mohit Gupta_OMG <(0_o)>

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Choose the correct term to complete the sentence.
lord [1]

Answer:

3.) Technology

Explanation:

Technology is pretty epic, my dude.

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How are actual rocket launches similar to how balloon rockets and canister rockets launch?
guajiro [1.7K]

Answer: in a net force acting forward on the balloon thrust.The balloon flies forward under the influence of the thrust, and the air coming out of the back of the balloon is the equal and opposite reaction to the thrust. same goes for a rocket

Explanation:

hoped this helped

8 0
3 years ago
Python provides a special version of a decision structure known as the ________ statement, which makes the logic of the nested d
IrinaVladis [17]

Answer:

if-elif-else                                            

Explanation:

In Python if condition is used to decide whether a statement or a block of statements is to be executed or not based on the condition, if the condition evaluates to true then the block of statements is executed and if the condition is false then it is not executed.

Sometimes we need to execute some other statement when the condition is false. For example

if (number1 <= number2)

print (number1,  "is the smallest")

Lets suppose we want to print another statement if this condition evaluates to false. If the condition gets false then the following message should be displayed:

print(number 2, "is the smallest")

For this purpose else statement is used along with if statement to execute the block of code when the if condition evaluates to false.

if (number1 <= number2)

print (number1,  "is the smallest")

else:

print(number 2, "is the smallest")

Now what if there are three numbers or more numbers to be compared in order to identify the smallest number from the given numbers. So in this case we have multiple options to be checked. else statement will not be enough a  for else there can be at most one statement. With if elif else multiple conditions can be checked and if any of the condition evaluates to true then its block of code is executed and if none of the condition is true then the last else statement will be executed.

For example:

if (number1 <= number2) and (number1 <= number3):

print (number1,  "is the smallest")

elif (number2 <= number1) and (number2 <= number3):

print (number1,  "is the smallest")

else:

print (number3,  "is the smallest")

In this example number1 is compared to number2 and number3. If both numbers are less than number1 then the program control goes to elif statement where number2 is compared to number1 and number3. if this condition is false too then the final else part will be printed which is that number3 is the smallest.

Take another example where there are more number of expressions to be checked.

val = 50

if (val == 40):  

   print ("value is 40")  

elif (val== 35):  

   print ("value is 35")  

elif (val == 25):  

   print ("value is 25")  

elif(val==15):

    print ("value is 15")  

else:  

   print ("value is not present")

This will output the else part value is not present, because none of the condition evaluates to true.

7 0
4 years ago
g The reciprocal Fibonacci constant ψ is defined by the infinite sum: ψ=∑n=1 [infinity] 1 Fn Where Fn are the Fibonacci numbers
timama [110]

Answer:

see explaination

Explanation:

MATLAB script:

% MATLAB script that calculates reciprocal Fibonacci constant Ψ

% Initial Values

a0 = 1;

a1 = 1;

% Looping variable

i = 2;

% Reading n value from user

n = input(' Enter n value: ');

% Initializing sum

sum = (1/a0) + (1/a1);

% Loop till i reaches n value

while i <= n

% Finding term in Fibnocii series

a2 = a0 + a1;

% Accumulating Sum

sum = sum + (1/a2);

% Updating previous terms

a0 = a1;

a1 = a2;

% Incrementing loop variable

i = i + 1;

endwhile

% Printing result

printf("\n Reciprocol Fibnocii Constant: %f \n", sum);

See attachment for sample output

5 0
3 years ago
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pochemuha

Answer:

The answer is Cascading

8 0
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