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3 years ago

10

A statistical analysis firm is hired to analyze the failure rate of a manufactured product. Which margin of error below would be

st indicate that the data used by the firm is a valid representation of the population?
7.6
2.1
3.3
8.9

1 answer:

True [87]3 years ago

4 0

The smaller the margin of error the better, so I would say 2.1

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Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people ans

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Answer:

Step-by-step explanation:

From the information given:

We can compute the required calculations into a table as shown below.

$\mathbf{Data \ value }$ $\mathbf{ Frequency }$ $\mathbf{Relative \ frequency}$ $\mathbf{Cumulative \ relative }$

$\mathbf{Frequency}$

5 14 14/65 = 0.22 14

6 19 19/65 = 0.29 19+14 = 33

7 12 12/65 = 0.19 33+12 = 45

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65

Note: that the relative frequency is determined by dividing each value in the frequency by the total of the frequency.

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3 years ago

2) Divide (8.6 x 108) by (3.2 x 103). Express your answer in scientific notation. <br> A) .26875 x 106 <br> <br> B) 2.6875 x 105

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4 years ago

The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprin

Rashid [163]

The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprinkler was 15 L per hour. The water output rate for the Perry family's sprinkler was 40 L per hour. The families used their sprinklers for a combined total of 65 hours, resulting in a total water output of 1850 L . How long was each sprinkler used

Answer:

Hours of use of sprinkler by Lewis family is 30 hours.

Hours of use of sprinkler by Perry family is 35 hours.

Step-by-step explanation:

Let W = hours of use by Lewis family

65 - W = hours of use by Perry family

Then;

15W + 40*(65 - W) = 1850

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Therefore;

W = 30

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Hence,

Hours of use by Lewis family is 30 hours.

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4 years ago

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Answer:

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3 years ago

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

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This equation can also be written as,

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Hence, Option a is the correct answer.

8 0

4 years ago

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