Question

8m^3 - 28m^2 + 6m - 21. You solve by factoring by grouping!!! quick please

Answer 1

Answer:

$(2m - 7)(4 {m}^{2} + 3)$

Step-by-step explanation:

$8m^3 - 28m^2 + 6m - 21 \\ = 4 {m}^{2} (2 {m} - 7) + 3(2m - 7) \\ = (2m - 7)(4 {m}^{2} + 3)$