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alukav5142 [94]
2 years ago
8

Given h(t) = -2(t+ 5)^2 +4, find h(-8).

Mathematics
1 answer:
bekas [8.4K]2 years ago
7 0

Answer:

Substitute -8 as x into the equation.

h(-8)=-2(-8+5)^2+4

h(-8)=-2(-3)^2+4

h(-8)=-2(9)+4

h(-8)=-18+4

h(-8)=-14

:)

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Step-by-step explanation:

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When she subtracts 4 from both sides, Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction x.
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brainly.com/question/11562149

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