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cricket20 [7]
4 years ago
9

A vehicle purchased for $20,700 depreciates at a constant rate of 7%. Determine the approximate value of the vehicle

Mathematics
2 answers:
Sonja [21]4 years ago
6 0

Answer:

$0

Step-by-step explanation:

(assuming straight line depreciation)

Recall that,

Depreciation Rate (%) = (Annual Depreciation / Initial Cost ) x 100%

or,

Annual Depreciation = Depreciation Rate x Initial Cost

Given that depreciation rate = 7% = 0.07 and the initial cost was $20,700,

Annual Depreciation = 0.07 x $20,700 = $1,449

Also recall that the following formula also applies:

Annual Depreciation = (Initial Cost - Final Value) / time

given that time is 15 years and the initial cost and annual depreciation is given above,

1449 = (20,700 - Final Value) / 15

(15)(1449) = 20,700 - Final Value

Final Value = 20,700 - (15)(1449)

Final Value = 20,700 - 21,753

Final Value = -$1,035

So we see that after 15 years, the car ends up with a negative value, (basically means the car has no value).

The nearest whole dollar to a negative dollar is simply zero

hence the approx value of the car is zero $0

tamaranim1 [39]4 years ago
5 0

Answer:

$22,000

Step-by-step explanation:

So, we would multiply 20,700 and 7%. That equals to 1,449

Then we would multiply 1,449 and 15 that equals 21,735.

SO after 15 years it will be worth 21,735

But then we would round it up, because it is above 500.

So the total value rounded up will be $22,000

Hope this helps!

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andrew-mc [135]

Answer:

Simply count 4 × 6 =28

Step-by-step explanation:

7 0
3 years ago
PLz help I will give brainliest!!!!! and extra points
Natalija [7]

Hey there!

<u></u>

The answer to your question is 95.55<u></u>

<u></u>

<u>Formulas:</u>

<u></u>

<em>Area of semi-circle = </em>\frac{1}{2}(\pi r^2)<em></em>

<em>Area of rectangle = </em>lw<em></em>

<em>Area of triangle = </em>\frac{bh}{2}<em></em>

<em></em>

<u>Now solve:</u>

<em>semi-circle</em>

\frac{1}{2}\pi3^2

\frac{1}{2}\pi9

4.5\pi

<em>(We will use 3.14 as approx. for pi)</em>

<em />4.5 * 3.14\\23.55

<em>rectangle</em>

10(6)\\60

<em>triangle</em>

<em />\frac{4(6)}{2}<em />

<em />\frac{24}{2} \\12<em />

<em>Now add them all together:</em>

<em />23.55+60+12\\95.55<em />

<em />

Have a terrificly amazing day!

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3 0
3 years ago
a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera
seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × (1-\dfrac{\textrm rate}{100})^{\textrm time}

Or, P = p × (1-\dfrac{\textrm r}{100})^{\textrm t}

Or, 8200 = 10225 × (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, \dfrac{8200}{10225} =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, 0.80195 =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

<u>Taking power \dfrac{1}{6} both side</u>

So, (0.80195 )^{\frac{1}{6}} = ((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}

Or, 0.9638 = 1 - \dfrac{r}{100}

Or,  \dfrac{r}{100} = 1 - 0.9638

Or,  \dfrac{r}{100} = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0
3 years ago
How can you use rates to determine whether a situation is a proportional relationship
gulaghasi [49]
Well your answer is
rate = constant
7 0
4 years ago
Read 2 more answers
Find the value of f(-4).
Alex

Answer:

y = f(x) = f(-4) =-4 because the value of f is equal to -4

4 0
2 years ago
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