Question

How much of a radioactive kind of calcium will be left after 10 days if the half-life is 5 days

Answer 1

Answer: 16 g

Step-by-step explanation:

We can solve this with the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$    

Where:

$A$ is the final amount of radioactive calcium

$A_{o}=64 g$ is the initial amount of radioactive calcium

$t=10 days$ is the time elapsed

$h=5 days$ is the half life of radioactive calcium

Solving with the given data:

$A=(64 g)2^{\frac{-10 days}{5 days}}$    

$A=16 g$  This is the amount of radioactive calcium left