Question

Find the​ range, variance, and standard deviation for the given sample data. Include appropriate units in the results.

Answer 1

Answer:

$Range = 1.48-0.63=0.850 W/kg$

$s= 0.320 W/Kg$

$s^2 = 0.320^2= 0.103 W^2 /kg^2$

D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.

Step-by-step explanation:

For this case we have the following data values:

0.95,0.73,0.63,0.91,1.32,1.48,0.63,1.23,0.91,1.41,0.67

The first step on this case is order the datase on increasing way and we got:

0.63 0.63 0.67 0.73 0.91 0.91 0.95 1.23 1.32 1.41 1.48

The range is defined as $Range = Max-Min$

And if we replace we got:

$Range = 1.48-0.63=0.850 W/kg$

The sample standard deviation is given by this formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got $s= 0.320 W/Kg$

And the sample variance is just the standard deviation squared so we got:

$s^2 = 0.320^2= 0.103 W^2 /kg^2$

And for the last question about : If one of each model is measured for radiation and the results are used to find the measures of​ variation, are the results typical of the population of cell phones that are in​ use?

We can conclude this:

D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.