Let f(x)=y
f^-1(x)=x
y=1/(x+5) - 1
y+1=1/(x+5)
(x+5)=1/(y+1)
x=1/(y+1)-5
f^-1(x)=1/(x+1) -5
denominator cannot equals to zero
x+1≠0
x≠-1
answer
B
<h3>
Answer: 1</h3>
Explanation:
The jump from 2 to 2&1/2 is an increase of 1/2
2 + 1/2 = 2 & 1/2
The jump from 2 & 1/2 to 1 & 1/2 is a decrease of 1
(2 & 1/2) - 1 = (2 - 1) & 1/2 = 1 & 1/2
The jump from 1 & 1/2 to 2 is an increase of 1/2
(1 & 1/2) + 1/2 = 1 + (1/2 + 1/2) = 1 + 1 = 2
The pattern seems to be "add 1/2, subtract 1". Assuming this is the case, we would then subtract 1 from the last term we got (2) to get 2-1 = 1
Answer:
option A
Step-by-step explanation:
Answer: 38 m
Step-by-step explanation:
5 + 2 + 2 = 9
9 * 2 = 18
4 * 5 = 20
18 + 20 = 38
Answer:
and 
Step-by-step explanation:
An algebraic expression is a polynomial if and only if the variables involve have positive integral indices or exponents.
The given polynomial is: 
We want to put one of the following polynomials in the blank space to create a fully simplified polynomial written in standard form.





A fully simplified polynomial written in standard form is obtained by writing the simplified polynomial in decreasing order according to degree.
Since the first term of
having a degree of 5 and the last term is having a degree of 3.
The polynomial that goes into the blank must have a degree of 4.
This eliminates
, 
and 
We are now left with
and 
The required polynomial is therefore
or
These two polynomials are in standard form and cannot be simplified further.
The correct choices are;
and 