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4 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Naddika [18.5K]4 years ago

6 0

Answer: B. 16

Step-by-step explanation:

1,536/6=256

256 squared=16

Marysya12 [62]4 years ago

4 0

Answer:

B. 16

Step-by-step explanation:

You need to work on the equation backwards. You know the answer, but you don’t know x. first, you divide 1536 by 6. you will get 256. next, you find the square root of 256. the square root of 256 is 16, so the answer is 16 :)

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siniylev [52]

Answer:

Slant height (s)= 12.1 cm

Step-by-step explanation:

Given: Base= 4.5 cm.

Surface area of right square pyramid= 129.5 cm.

First, calculating slant height (s) of right square pyramid.

Surface area of square pyramid= $(a^{2} +2\times a\times s)$

a= side of square base.

s= slant height

∴ $129.5= (4.5^{2} + 2\times 4.5\times s)$

⇒ $129.5= (20.25+2\times 4.5\times s)$

⇒ $129.5= (20.25+9\times s)$

Now, opening the parenthesis and subtracting both side by 20.25.

⇒ $109.25=9\times s$

cross multiplying both side

∴ Slant height (s)= 12.1

5 0

4 years ago

The function of f(x) varies directly with x, and f(x)=48 when x=8. Evaluate f(x) when x=2

lara31 [8.8K]

Here's the equation for direct variation. k=y/x [ f(x)=y]
Find k
k= 48/8=6
6=y/2
y=12
Hope this helps.

5 0

3 years ago

Maggie is standing in her front yard and measures the length of the shadow she casts, as well as the shadow, cast by her house.

zimovet [89]

Answer:

the answer is 57

Step-by-step explanation:

because you round to the nearest foot which it means that the answer good luck hope this helps

3 0

3 years ago

The linear equation x=5 would be a graph of a..

Lelechka [254]

Thw answer to your Problem would be A

7 0

4 years ago

The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in

Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

* Lets explain how to solve the problem

- Any point will be equidistant from the x-axis and the y-axis must have

equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

because the distance from the x-axis to the point is 4 (y-coordinate)

and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then

$x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

* Lets solve the problem

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ $x=\frac{p+p+2q}{2}$

∴ $x=\frac{2p+2q}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $x=\frac{2(p+q)}{2}$

- Divide up and down by 2

∴ x = p + q

∵ $y=\frac{q+q+2p}{2}$

∴ $y=\frac{2q+2p}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $y=\frac{2(q+p)}{2}$

- Divide up and down by 2

∴ y = q + p

∴ The mid point of AB is (p + q , q + p)

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

x-axis and the y-axis

8 0

3 years ago