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1 answer:
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The equation of the circle with center (h, k) and radius r is
.. (x -h)^2 +(y -k)^2 = r^2
1. selection D matches the specification of the circle
2. selection A matches the given equation
3. None of the offered selections matches
.. (x -3)^2 +(y -5)^2 = 74
4. selection A matches the requirements
.. (x -h)^2 +(y -k)^2 = r^2
1. selection D matches the specification of the circle
2. selection A matches the given equation
3. None of the offered selections matches
.. (x -3)^2 +(y -5)^2 = 74
4. selection A matches the requirements
Answer:
3
Step-by-step explanation:
We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.
To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:
Then to resolve a quadratic equation we apply Bhaskara's formula:
It usually has two solutions.
But it could happen that then the equation doesn't have real solutions.
Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.
And it's not possible to have more than 2 solutions. Then the answer ir 3.
For example:
In the three graphs the pink one is a quadratic function and the green one is a linear function.
In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.
In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.
In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.
Answer:
15 units
Step-by-step explanation:
d = 14.866
d = 15