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viva [34]
3 years ago
5

Plz answer as many as you can...

Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0
4/11,9/13,6/25,0.48,0.624
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Which polygon is a base of the triangular prism?
V125BC [204]

A pyramid or triangular prism is a polyhedron that has a base, which can be any polygon, and three or more triangular faces that meet at a point called the vertex.

<u>Explanation:</u>

  • These triangular sides are sometimes called the lateral faces to distinguish them from the base.
  • It is a polyhedron that has a base, which can be any polygon, and three or more triangular faces that meet at a point called the vertex.
  • The base of the triangular prism is in the shape of a quadrilateral and the lateral face is in the shape of a triangle.
6 0
3 years ago
Read 2 more answers
Write the standard equation for the circle.
Kay [80]
The equation of the circle with center (h, k) and radius r is
.. (x -h)^2 +(y -k)^2 = r^2

1. selection D matches the specification of the circle

2. selection A matches the given equation

3. None of the offered selections matches
.. (x -3)^2 +(y -5)^2 = 74

4. selection A matches the requirements

3 0
2 years ago
Brayden's horse gained 9 pounds over a 3 week
mr_godi [17]
30 pounds after 10 weeks
9/3=3
3*10=30
5 0
3 years ago
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Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
I'm stuck, plsss help ASAPP!!! :))
Bogdan [553]

Answer:

15 units

Step-by-step explanation:

d \:  =  \sqrt{(x2 - x1) ^{2}  + (y2 - y1) ^{2} }

d = 14.866

d = 15

7 0
3 years ago
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