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viva [34]
3 years ago
5

Plz answer as many as you can...

Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0
4/11,9/13,6/25,0.48,0.624
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UJ 1641"
Alekssandra [29.7K]

Answer:

t

Step-by-step explanation:

7 0
3 years ago
Solve by completing the square<br>3x2 + x - 2 = 0​
DIA [1.3K]

Answer:

x = 2/3 or x = -1

Step-by-step explanation by completing the square:

Solve for x:

3 x^2 + x - 2 = 0

Divide both sides by 3:

x^2 + x/3 - 2/3 = 0

Add 2/3 to both sides:

x^2 + x/3 = 2/3

Add 1/36 to both sides:

x^2 + x/3 + 1/36 = 25/36

Write the left hand side as a square:

(x + 1/6)^2 = 25/36

Take the square root of both sides:

x + 1/6 = 5/6 or x + 1/6 = -5/6

Subtract 1/6 from both sides:

x = 2/3 or x + 1/6 = -5/6

Subtract 1/6 from both sides:

Answer:  x = 2/3 or x = -1

3 0
3 years ago
After driving to a riverfront parking lot, Bob plans to run south along the river, turn around, and return to the parking lot, r
mars1129 [50]

Answer:A) 1.5

Step-by-step explanation: Bob runs at the rate of 8mins per mile

In 60mins his rate would be=60/8=7.5

Let a be the distance he further runs south

2s+3.25

Total distance covered in 50mins=Time=distance/speed=

50/60

50/60=2s +3.25/7.5

Cross multiply

60(2s+3.25)=50×7.5

120s+195=375

120s=375-195

S=180/120

S=1.5

5 0
3 years ago
If f(x) = 2x2 + 1 and g(x) = x2 – 7, find (f – g)(x).
nadya68 [22]

Answer:  The required value is

(f-g)(x)=x^2+8.

Step-by-step explanation: The given functions are:

f(x)=2x^2+1,\\\\g(x)=x^2-7.

We are given to find the value of (f-g)(x).

We know that, if s(x) and t(x) are any two functions of a variable x, then we have

(s-t)(x)=s(x)-t(x).

Therefore, we have

(f-g)(x)\\\\=f(x)-g(x)\\\\=(2x^2+1)-(x^2-7)\\\\=2x^2+1-x^2+7\\\\=x^2+8.

Thus, the required value is

(f-g)(x)=x^2+8.

5 0
3 years ago
B. Why does using FOIL on polynomial expressions match so closely to integer
Anastasy [175]
FOIL is a mnemonic rule for multiplying binomial (that is, two-term) algebraic expressions.
FOIL abbreviates the sequence "First, Outside, Inside, Last"; it's a way of remembering that the product is the sum of the products of those four combinations of terms.

For instance, if we multiply the two expressions
(x + 1) (x + 2)
then the result is the sum of these four products:
x times x (the First terms of each expression)
x times 2 (the Outside pair of terms)
1 times x (the Inside pair of terms)
1 times 2 (the Last terms of each expression)
and so
(x + 1) (x + 2) = x^2 + 2x + 1x + 2 = x^2 + 3x + 2
[where the ^ is the usual way we indicate exponents here in Answers, because they're hard to represent in an online text environment].

Now, compare this to multiplying a pair of two-digit integers:
37 × 43
= (30 × 40) + (30 × 3) + (7 × 40) + (7 × 3)
= 1200 + 90 + 280 + 21
= 1591

The reason the two processes resemble each other is that multiplication is multiplication; the difference in the ways we represent the factors doesn't make it a fundamentally different operation.
7 0
3 years ago
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