All categories

2 years ago

Which crustaceans form the base of many food chains

Mathematics

1 answer:

Anettt [7]2 years ago

4 0

Answer:

Step-by-step explanation:

Primary producers — including bacteria, phytoplankton, and algae — form the lowest trophic level, the base of the aquatic food web. ...

Some zooplankton including copepods, rotifers, larval stages of some fish and invertebrates are grazers and drift through the water grazing on phytoplankton.

You might be interested in

Select the correct answer

Marta_Voda [28]

Answer:

Step-by-step explanation:

reason for is because when you add all the like terms you end up with c

6 0

3 years ago

What is the midpoint of the line segment (-8,-7) and (-7,-8)

goblinko [34]

The answer is (-7.5, -7.5)

3 0

3 years ago

What is 8777 divided by 456

zimovet [89]

Your answer is 19.25.

8 0

3 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Let f(x)=x2−16x+71 .what is the vertex form of f(x)?what is the minimum value of f(x)? enter your answers in the boxes.

adell [148]

Your vertex is (8,7)

First find the x intercept
-2/2a

X = 16/2
X = 8

Substitute the value x and solve for y
Youd get 7

Hence
(8,7)

7 0

3 years ago

Read 2 more answers