1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blizzard [7]
3 years ago
14

The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.

Mathematics
1 answer:
Feliz [49]3 years ago
4 0
QR=9
QP=6
TU=19
TS=?
Okay so the triangles are kindred, now the equation can be made
9/16=6/x
So now we are going to cross multiply
9x=114
Now divide both sides by
912 2/3
Your answer is:
TS=12.6
You might be interested in
in a regular polygon each interior angle is 140 greater than each exterior angle calculate the number of sides of each polygon .
Elodia [21]

Answer:

9

Step-by-step explanation:

Exterior sides =  180 - 140 = 40

number of sides = 360 / 40 = 9 sides

6 0
3 years ago
A tire dealer sells 2 tires for as much as he paid for 3 tires. he paid $240 for a dozen tires. What is the total profit on 12 t
tester [92]
First, find how much he paid by tire.
To do so, divide what he paid by how many tires he bought like this :
240$ / 12 = 20$ per tire

Then, calculate how much he sells each tire.
To do so, start by calculating how much he paid for 3 tires:
20$ x 3 = 60$

This is the price he sells 2 tires for, therefore :
60$ / 2 = 30$
he sells his tires 30$ each.

Finally, you have to calculate the profit he made by selling 12.
We already know how much it cost, so you need to find how much money he gets selling them :
12 tires x 30$ = 360$

To find the profit, take off the amount he paid from the amount he made :
360$ - 240$ = 120$

There you go!
3 0
3 years ago
Carpet, padding, and installation costs $23.23 per sq. yd. how much would it cost to carpet both bedrooms.
MAVERICK [17]
$46.46 for both rooms to have carpet
4 0
3 years ago
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
Select the graph that best represents the solution set of the system of linear inequalities
Butoxors [25]
I think C
Hope it helps
3 0
2 years ago
Other questions:
  • Which of the following equations is non-linear?
    12·1 answer
  • Mike took a taxi from his home to the airport. The taxi driver charged an initail $6 plus $3 per mile. The total fare was $24, n
    13·1 answer
  • Help plz
    5·1 answer
  • If x4 + 4y = 8xy, then dy/dx=
    11·1 answer
  • What are the 6 trigonometric functions of (4,-2) and (-9,-9)
    15·1 answer
  • I WILL GIVE AN EXTRA 50 POINTS TO WHOEVER GETS THESE 2 QUESTIONS RIGHT
    7·1 answer
  • Yo 9th grade algebra 2 just answer the bottom row i did the rest by myself.
    10·1 answer
  • The calories I burn walking can be modeled by the function y = 5x + 100,
    10·1 answer
  • If p is the probability of success of a binomial experiment, then the probability of failure is what?
    12·1 answer
  • OFind the missingangle measures.B.m 41 =9058°A4m 42 =31089Em 3 =o
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!