Suppose a and b are integers. If a - b = -7, What is b -a?

(03.01 MC) The length of a rectangle is 5 units and its width is 4 units. What is the approximate length of the diagonal of the

Alexxandr [17]

Answer:

√41, or about 6.4 units

Step-by-step explanation:

$\sqrt{ {5}^{2} + {4}^{2} } = \sqrt{25 + 16} = \sqrt{41}$

√41 is about 6.4 units

4 0

1 year ago

When Jonas becomes the Receiver of Memory, he gets a rule that he may not tell his dreams. He wants to know how many of his 5050

Naya [18.7K]

Answer:

101010 classmates can't tell their dreams.

Step-by-step explanation:

I'm not sure what the question is, but if it is an average thing than 444 of 555 is 80 percent, so if that is what it wants 404040 of the students can share their dreams, and 101010 can't.

Hope this helps!

4 0

3 years ago

Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago

X(x+3) + 34 = (x +5)(x+2)

My name is Ann [436]

X(x + 3) + 34 = (x + 5)(x + 2)

First, expand to remove parentheses.
$x^{2} + 3x + 34 = x^{2} + 2x + 5x + 10$
Second, add '2x + 5x' to get '7x'.
$x^{2} + 3x + 34 = x^{2} + 7x + 10$
Third, cancel out ' $x^{2}$ ' on both sides.
$3x + 34 = 7x + 10$
Fourth, subtract '3x' from both sides.
$34 = 7x + 10 - 3x$
Fifth, subtract '7x - 3x' to get '4x'.
$34 = 4x + 10$
Sixth, subtract '10' from both sides.
$34 - 10 = 4x$
Seventh, subtract '34 - 10' to get '24'.
$24 = 4x$
Eighth, divide both sides by '4', leaving the 'x' by itself.
$\frac{24}{4} =x$
Ninth, since '24 ÷ 4 = 6', simplify the fraction to '6'.
$6 = x$
Tenth, switch your sides to get the answer.
$x = 6$

Answer: x = 6

4 0

3 years ago

What is y=3x^2-2 in vertex form

Nata [24]

$\bf \qquad \qquad \textit{parabola vertex form}
\\\\\\
y=a(x-{{ h}})^2+{{ k}}\\
x=a(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
y=3x^2-2\iff y = 3(x-0)^2-2$

3 0

3 years ago