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3 years ago

Write a mix number as a faction 43/8

Mathematics

2 answers:

klemol [59]3 years ago

8 0

Answer:

5 3/8

Step-by-step explanation:

First we see how many times the denominator goes into the numerator.

8 goes into 43 five times; this means 5 is our whole number.

5(8) = 40; this leaves 43-40 = 3 remaining. This is our numerator.

This gives us 5 3/8.

butalik [34]3 years ago

7 0

Answer:

5 3/8

Step-by-step explanation:

43/8

8 goes into 43 5 times with 3 left over so your answer will be

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This table shows the number of different sized pipes that have been used at Highfield Builders in January.

mote1985 [20]

Answer:

Mean diameter = 44, which is in the 40 - 44 cm group

Step-by-step explanation:

Given the data:

Diameter (cm) - mid point(X) - frequency(F) - - FX

35-39 - - - - 37 - - - - 8 - - 296

40-44 - - - 42 - - - 10 - - - 420

45-49 - - - 47 - - - 13 - - - 611

50-54 - - - 52 - - - 3 - - - 156

55-59 - - - 57 - - - 1 - - - 57

Mean of grouped data:

Sum of (F × X) / sum of F

1540 / 35 = 44

8 0

4 years ago

What is 2 divided by 1,1132?

telo118 [61]

Answer: 1/5566

Step-by-step explanation: Try division or simplifying fractions concepts to solve this.

8 0

3 years ago

Can I please have help with question 2) a and b

Ulleksa [173]

Answer:

$\frac{10\sqrt{6} }{3}$ and $\frac{11\sqrt{3} }{3}$

Step-by-step explanation:

(a)

A = $\frac{1}{2}$ × 4 $\sqrt{2}$ × $\frac{5}{\sqrt{3} }$

= 2 $\sqrt{2}$ × $\frac{5}{\sqrt{3} }$

= $\frac{10\sqrt{2} }{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ ← rationalise the denominator

= $\frac{10\sqrt{6} }{3}$ units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4 $\sqrt{2}$ )² + ( $\frac{5}{\sqrt{3} }$ )²

= 32 + $\frac{25}{3}$

= $\frac{96}{3}$ + $\frac{25}{3}$

= $\frac{121}{3}$ ( take the square root of both sides )

h = $\sqrt{\frac{121}{3} }$ = $\frac{11}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ ← rationalise the denominator

h = $\frac{11\sqrt{3} }{3}$

7 0

3 years ago

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim

geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

$\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i$

$[a, b] = [-8, 6]$

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x$

Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$

Therefore, the answer to the integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

5 0

3 years ago

△ABC∼△EFG .<br><br> Given m∠C=52° and m∠E=61° , what is m∠B ?

Alexandra [31]

Did you you get the answer to this one?

6 0

3 years ago

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