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Morgarella [4.7K]
3 years ago
13

Brainest for best answer only 5 mins left show your work

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

Step-by-step explanation:

Problem One

Perimeter is in meters not square meters. The equation is

2*(6.8+x) + 2*12.5= 47                Remove the brackets. Combine like terms  

13.6 + 2x + 25 = 47

38.6 + 2x = 47                            Subtract 38.5 from both sides

2x = 47 - 38.6  

2x = 8.4                                      Divide by 2

x = 4.2

Answer D

Problem 2

This problem is asking that you calculate the perimeter of a swimming pool.

The two semicircles on the ends make a whole circle.

The diameter of the semicircles is obtained from the difference of the two given lengths.

The rectangle has a length of 12. The length of the rectangle and the 2 semicircles is 16. The difference is 4. You could divide this by 2 to get the radius. I would just leave it as the diameter.

So the perimeter is pi*d + 2 * 12 [there are 2 lengths]

Perimeter = 4*pi + 24

Perimeter = 12.56 + 24

Perimeter = 36.56

Answer A

Problem 3

This is the circle inside the square.

The radius of the circle = 9

The diameter of the circle and the length of square's side = 2*9 = 18

The area of the square = s^2  where s = 18

The area of the square = 18^2 = 324

The area of the circle = pi * 9^2 = 3.24 * 81 = 251.34

The area of the Shaded area = 324 - 251.34 = 69.66

Answer C

Problem 4

b1 = 5

b2 = 11.5

h = 4.5

Formula

Area = (b1 + b2 ) * 4.5/2

Area =  (5 + 11.5) * 4.5 /2

Area = 16.5 * 4.5 / 2

Area = 74.25/2

Area = 37.125

Answer D

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Step-by-step explanation:

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3 0
3 years ago
Does anyone know how to do this help please
statuscvo [17]

Answer:

\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

\rm\implies y = x^2+x - 6

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2-3-6\\

\rm\implies y = 9 - 3 - 6 \\

\rm\implies y = 0

<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2-2-6\\

\rm\implies y = 4 -2-6\\

\rm\implies y = -4

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = -1^2-1-6\\

\rm\implies y = 1 -1-6 \\

\rm\implies y = -6

<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 1^2+1-6\\

\rm\implies y = 2 -6

\rm\implies y = -4

<u>Put </u><u>x </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 2^2+2-6\\

\rm\implies y = 4 +2-6\\

\rm\implies y = 2

<u>Put </u><u>x </u><u>=</u><u> </u><u>3 </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 3^2+3-6\\

\rm\implies y = 9 +3-6\\

\rm\implies y = 6

<u>Final </u><u>table</u><u> </u><u>:</u><u>-</u><u> </u>

\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}

7 0
3 years ago
Plz help thank you thank you
natta225 [31]

Answer:

B

Only one that goes over once and up twice

6 0
3 years ago
Read 2 more answers
Question:
NNADVOKAT [17]

1.) 9(4) + 8(5)

36 + 40 = 74

2.) 2(3) + 8(3)

6 + 24 = 30

3.) 4(5) + 7(5)

20 + 35 = 55

4.) 10(4) + 18(5)

40 + 90 = 130

5.) 2 + 8(1/4)

2 + 2 = 4

6.) 9(1/3) + 8(1/4)

3 + 2 = 5

7.) 3(8) + 7(4)

24 + 28 = 52

8.) 12(1/4) + 16(5)

4 + 80 = 84

8 0
3 years ago
The points (-4,r) and (2,-3) lie on a line with a slope-1. Find the missing coordinator r.?
MAVERICK [17]

Answer:

3 (-4,3)

Step-by-step explanation:

7 0
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