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Alborosie
3 years ago
11

What is the solution to the equation? round your answer to two decimal places. 6•e^x=25​

Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Given

6e^{x} = 25 ( divide both sides by 6 )

e^{x} = \frac{25}{6}

Take the ln of both sides

lne^{x} = ln (\frac{25}{6}) , hence

x lne = ln (\frac{25}{6}) ← note ln e = 1

x = ln (\frac{25}{6}) ≈ 1.43 → A

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Answer:

25%

Step-by-step explanation:

100-80=20

20/80Ⅹ100=25%

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2 years ago
1.
vaieri [72.5K]

Answer:

2nd option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- \frac{3}{2}, 0) and (x₂, y₂ ) = (0, \frac{3}{4} )

m = \frac{\frac{3}{4}-0 }{0+\frac{3}{2} } = \frac{\frac{3}{4} }{\frac{3}{2} } = \frac{1}{2} and c = \frac{3}{4} , then

y = \frac{1}{2} x + \frac{3}{4} ( multiply through  by 4 to clear the fractions )

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6 0
3 years ago
What is the equation ?
Alexandra [31]

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Graph the plotted points!

Step-by-step explanation:

4 0
3 years ago
What's the hinge theorem and it's converse?
Elena L [17]
The converse of the hinge theorem is also true: If the two sides of one triangle are congruent<span> to two sides of another triangle, and the third side of the first triangle is greater than the third side of the second triangle, then the included angle of the first triangle is larger than the included angle of the second .</span>
7 0
4 years ago
The fish population in a pond with carrying capacity 1200 is modeled by the following logistic equation where N(t) denotes the n
MArishka [77]

9514 1404 393

Answer:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

  142 fish

Step-by-step explanation:

A) The differential equation is modified by adding a -50 fish per year constant term:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

__

B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.

  (0.4/1200)(N)(1200-N) -50 = 0

  N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient

  N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square

  (N -600)^2 = 210,000 . . . . . simplify

  N = 600 + √210,000 ≈ 1058

This steady-state number of fish is ...

  1200 - 1058 = 142 . . . . below the original carrying capacity

8 0
3 years ago
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