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3 years ago

What is the solution to the equation? round your answer to two decimal places. 6•e^x=25

Mathematics

1 answer:

wolverine [178]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

6 $e^{x}$ = 25 ( divide both sides by 6 )

$e^{x}$ = $\frac{25}{6}$

Take the ln of both sides

ln $e^{x}$ = ln ( $\frac{25}{6}$ ) , hence

x lne = ln ( $\frac{25}{6}$ ) ← note ln e = 1

x = ln ( $\frac{25}{6}$ ) ≈ 1.43 → A

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Answer:

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2 years ago

For this function:

galina1969 [7]

Answer:

Minimum of t = $-\infty$

Maximum of t = $+\infty$

Minimum of h(t) = $-\infty$

Maximum of h(t) = +20

$D(-\infty,+\infty)$

$R(-\infty,+20]$

Step-by-step explanation:

Here in this problem, we are given the function, which is

$h(t)=-5t^2+20$

We observe immediately the following:

- The function has no limitations on the value of t - in fact, it contains no square roots, no logarithms, and no fractions; therefore, every value of x is acceptable in this function. This means that it has the variable t has no minimum or maximum values.

- On the other hand, h(t) cannot take any value. In fact, we notice that this is a quadratic function with the second-degree term with a negative coefficient: this means that it is a downward parabola. So, it has no downward limit (it goes to $-\infty$ ), but it has a maximum, which corresponds to the vertex of the parabola.

The x-coordinate of the parabola is given by

$x_v = -\frac{b}{2a}=0$

because the coefficient of the 1st-degree term, b, is zero. So, the y-coordinate of the vertex is

$h(0)=-5\cdot 0^2+20 = 20$

So, the maximum of h(t) is 20. Therefore we have:

Minimum of t = $-\infty$

Maximum of t = $+\infty$

Minimum of h(t) = $-\infty$

Maximum of h(t) = +20

The domain of a function is defined as the set of values of the independent function x for which the function has a valid value.

Therefore in this case, the domain of h(t) is the set of all values allowed for t: so, from part C, we can say that the domain is

$D(-\infty,+\infty)$

So, all real values.

The range of a function instead is the set of all values of the dependent variables, y.

So in this case, the range of h(t) is the set of all values that h(t) can take.

From part C, we know therefore that the range is

$R(-\infty,+20]$

Where +20 has the ] instead of ) because it is also an allowed value.

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3 years ago

Х<br> 120<br> 50<br> What is the value of x?

lara [203]

Answer:

Step-by-step explanation:

180-120= 60

a line is 180 degrees and x is congruent to the angle on the right of 120, meaning if you find the missing angle to that angle(the one next to 120) then you'd get the answer. Knowing the line it 180 and 120 is supplementary to x. x=60.

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2 years ago

Whats the sum of 2x and 3

uranmaximum [27]

<h2>Answer:</h2><h2>2x + 3</h2><h2></h2><h2>This is because you can't add a number that has a variable in it with one that doesn't</h2><h2></h2><h2>Hope this helps!!</h2>

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2 years ago

Please help with problem

Likurg_2 [28]

9514 1404 393

Answer:

∠CAE ≈ 16.7°
DF ≈ 5.3

Step-by-step explanation:

a) Angle CAE can be found using the tangent relation.

tan(∠CAE) = CE/AE

tan(∠CAE) = 6/20

∠CAE = arctan(6/20) ≈ 16.7°

b. The length of DF can be found using the law of cosines.

DF² = FA² +DA² -2·FA·DA·cos(A)

DF² = 14² +10² -2·14·10·cos(16.7°) ≈ 27.8086

DF ≈ √27.8086

DF = 5.3

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2 years ago

What is the solution to the equation? round your answer to two decimal places. 6•e^x=25​

What is the solution to the equation? round your answer to two decimal places. 6•e^x=25