How do you change a mixed number to an improper fraction?

1 answer:

Nookie1986 [14]3 years ago

4 0

Example: 2 1/2 = 5/2
You change a mixed number into an improper fraction by multiplying the whole number by the denominator and the add that onto the numerator. In the example shown above, you times the whole number (2) by the denominator (2) which equals 4, and then add that onto the numerator (1) which equals 5. So it becomes 5 over two. Hope this helps

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2.) Combine like terms and simplify the expression: 2x +<br> 5y+ 7x<br> Your answer

SashulF [63]

Answer:

9x + 5y

Step-by-step explanation:

Here, in 2x + 5y+ 7x, the 'like terms' are 2x and 7x, and the sum of these terms is 9x. Thus, 2x + 5y+ 7x becomes 9x + 5y.

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2 years ago

Two more than the quotient of a number and 6<br> is equal to 8

xxTIMURxx [149]

Answer:

Step-by-step explanation:

"Two more" = + 2

"quotient of a number and 6" = n/6

"equal to 8" = = 8

Set the equation:

n/6 + 2 = 8

Isolate the variable n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 2 from both sides.

n/6 + 2 (-2) = 8 (-2)

n/6 = 8 - 2

n/6 = 6

Isolate the variable n. Multiply 6 to both sides.

(n/6)(6) = (6)(6)

n = 6 * 6

n = 36

36 is your answer.

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3 years ago

Hurrrrryyyyyyyyy A triangle is reduced.

slamgirl [31]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .