Question

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7). What are the coordinates of point K" on the final image? (–7, –4) (–4, –7) (4, –7) (4, 7)

Answer 1

Answer:

Option C.

Step-by-step explanation:

Consider the complete question is "Triangle JKL is transformed using the rule $R(O,90^\circ)\circ r_{y=-x}(x,y)$. Point K of the pre-image is at (4, 7). What are the coordinates of point K'' on the final image?".

According to $r_{y=-x}(x,y)$, we get

$(x,y)\rightarrow (-y,-x)$

According to $R(O,90^\circ)$, we get

$(x,y)\rightarrow (-y,x)$

The rule $R(O,90^\circ)\circ r_{y=-x}(x,y)$ means first reflection and then rotation.

We need to find the image of K(4,7).

After reflection, we get

$K(4,7)\rightarrow K'(-7,-4)$

After rotation, we get

$K'(-7,-4)\rightarrow K''(4,-7)$

Therefore, the correct option is C.

Answer 2

Answer: C

(4, –7)

Step-by-step explanation:

(–7, –4)

(–4, –7)

(4, –7)

(4, 7)