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3 years ago

if a bathtub is being filled at a rate of 2.5 gallons per minute, how long will it take to fill the bathtub?

Mathematics

2 answers:

umka2103 [35]3 years ago

3 0

You need say how big the bathtub it is or you cant do it.

type the rest and ill try to answer it

Tatiana [17]3 years ago

3 0

Answer:

Let x = number of minutes

( 2.5 liters/min )*(x) = 30 liters

x = (30 liters) / (2.5 liters/min)

x = 30/2.5 min [note how liters cancel]

x = 12 min

Check:

Is 2.5*12 = 30 ?

30 = 30 ?yes

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Find the PERIMETER and AREA of each figure below

Oduvanchick [21]

Answer:

22)

$2(length+breadth+h)$

$2(5a^2b^2+3ab^2)$

$Perimeter: 2ab^2(5a^2+31)$

$Area:-$

$5a^2b^4 *3ab^2$

$A=15a^2b^6$

-----------

23)

$perimeter:-$

$4m^2+3mn^2+7mn$

$4m^2+10mn^2$

$answer: 2m(2m+5n^2)$

$Area:-$

$\frac{1}{2}* base* height$

$1/2*3mn^2*4m^2$

$6mx^{2+1}n^2$

$A=6m^3n^2$

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24)

$1/2*b*h$

$1/2x^24m^2*8mn$

$A=16m^3n$

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25)

$1/2*(7a^2b+11a^2b)*3ab$

$1/2*18a^2b*3ab$

$9a^2b*3ab$

$A=27 a^3b^2$

------------

26)

$A= 9\pi (x^3y)^2$

∴To calculate the perimeter , add the length of its sides.

∴To calculate the area, multiply its height by its width.

------------------------

hope it helps...

have a great day!!

8 0

3 years ago

In parallelogram ABCD, one way to prove the opposite sides are congruent is to draw in auxiliary line BD, then prove triangle AB

valina [46]

Answer: ASA congruency postulate

Step-by-step explanation:

Given: Parallelogram ABCD

To prove: ΔABD ≅ ΔBCD

Construction: Draw auxiliary line BD [see in the attachment]

Proof :- In ΔABD and ΔBCD

∠ADB=∠DBC [if lines are parallel, then its alternate interior angles are equal]

BD=BD [common]

∠ABD=∠BDC [if lines are parallel, then its alternate interior angles are equal]

⇒ΔABD ≅ ΔBCD [ASA congruency postulate]

⇒AD=BC and AB=CD [CPCTC]

ASA postulate tells if two angles and the included side of one triangle are equal to the corresponding parts of another triangle, then the triangles are congruent.

5 0

3 years ago

Read 2 more answers

What is the sample space of answering a true or false question? a. 1 b. 2 c. 4 d. 5

MissTica

Answer:

I think maybe B not 100% sure

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

3 years ago

the sum of four times the first number and three times the second number is 15. the difference of three times the first number a

Nana76 [90]

Hey there!

Let's create a systems of equations using x and y.

4x+3y=15

3x-2y=7

We need to solve this using elimination. First, we need to multiply the first equation by 2/3 so that we can cancel out the y's when combining our equations.

2 2/3x+2y=10

3x-2y=7

Now we combine the equations...

5 2/3x=17

x=3

Now we can plug our x into the first equation to find y.

12+3y=15

y=1

Our numbers are 3 and 1.

I hope this helps!

3 0

3 years ago